Question

a restaurant can seat 100 people . it has booths that seat 4 people and tables that seat 6 people.so far , 5 of the booths are full . what expression matches the situation?

Answer 1

$4(5)\\20\\\\4b+6t=100\\4(b-5)+6t=80\\2(b-5)+3t=40$

Answer 2

For this case, the first thing we must do is define variables.
 We have then:
 b: number of booths
 t: number of tables
 We write the expression that models the problem.
 We know that 5 of the booths are full.
 Therefore, the available space is:
 $4 (b-5) + 6t = 100$
 Rewriting we have:
 $4b - 20 + 6t = 100 4b + 6t = 100 + 20 4b + 6t = 120$
 Simplifying we have:
 $2b + 3t = 60$
 Answer:
 An expression that matches the situation is:
 $2b + 3t = 60$