Answer is: 3·10⁻⁴ mol of silver atoms. N(silver-Ag) = 1,8·10²⁰. n(Ag) = N÷Na. n(Ag) = 1,8·10²⁰ ÷ 6·10²³ 1/mol = 0,0003 mol = 3·10⁻⁴ mol. N - number of atoms of silver. Na - Avogadro number or Avogadro constant ( 6·10²³ mol⁻¹).¹ n - amount of substance.