Well, to began I suggest factoring out the expression on your own, correctly, to find the mistake they made.
I use to series of blanks to do this as follows:
6x^2-3x-9
3(2x^2-x-3)
i)
__ * __ =-3
(2)__ + __= -1
ii)
1 * -3= -3
(2)1 + -3 = -1
3(2x-3)(x+1)=0
From this form we can derive the x values as 3/2, and -1 if we needed to do so
Explanation:
Although these expressions are equivilant, Jamal's function is more coherent. He expresses that x+1=0 which can be solved as x=-1 rather than having to do 3x+3=0 => 3x=-3 => x=-1. Jamal's factor gives the function within a single step.
This form is the simplest form possible as Jamal noticed that the trinomial was divisible by 3 initially. Jennifer on the other hand did not factor out the 3 initially in the equation. As a result, here function less coherently states the properties of the function.
Hope this helps.
