Water flows over a section of niagara falls at the rate of 1.2x10^6 and falls 50.0 m. how much power is generated by the falling water

Respuesta :

The solution for this is:

 

Power = Energy transferred / Time taken 

Energy Transferred in one second ( Power) = mgh/s 

= (1.2x10^6)(9.8)(50) = 588000000 J/s 

Power = 588000000 W

 

Or

 

Power is work done / time 


Work done in one second = [ rate of fall of mass]

gh = 1.2* *9.81*50 x 10^6 J/s

= 5.886e+8 W

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