Question

Consider two objects (object 1 and object 2) moving in the same direction on a frictionless surface. object 1 moves with speed v1=v and has mass m1=2m. object 2 moves with speed v2=2√v and has mass m2=m. part a which object has the larger magnitude of its momentum?

Answer 1

By definition, we know that momentum is given by p = m * v. Then, for object 1, we have p1 = (2 * m) * (v) = 2mv and for object 2 we have p2 = (m) * ( sqrt(2) v) =  m*sqrt(2)v. Therefore, the moment magnitude for object 1 is greater than object 2  p1 > p2

Answer 2

Answer:

Object 1 have great momentum than object 2 .

Explanation:

Given :

Speed and mass of object 1 is v and 2m respectively .

Speed and mass of object 1 is $\sqrt 2v$ and m respectively .

We are required to find which object has the larger magnitude of its momentum.

We know, momentum , P = mv .

Momentum of object 1 , $P_1=2mv.$

Momentum of object 2 , $P_2=\sqrt 2mv.$

Comparing momentum of object 1 and 2 .

So, object 1 have great momentum than object 2 .

Hence, this is the required solution.