Both boys are applying forces to the wagon in the same direction,
so the result of both of them is a simple sum of the individual
magnitudes, and still in the same direction.
That's (6N east + 4N east) = 10 N east.
That's the net force due to the two boys.
IF there are no OTHER forces on the wagon,
then it's also the net force on the wagon. 10 N east