Question

how many moles of 2 are required to prepare 2.00 litters of 0.700m CaCl2

Answer 1

Answer:1.4 moles of calcium chloride are required.

Explanation:

Molarity of the calcium chloride solution = 0.700 M = 0.700 mol/L

Volume of the solution = 2 L

Moles of the calcium chloride = x

$Molarity=\frac{\text{moles of the substance}}{\text{volume of the Solution (L)}}$

$0.700 mol/L=\frac{x}{2 L}$

x = 1.4 moles of calcium chloride

1.4 moles of calcium chloride are required.