Respuesta :
Both objects move away from the site of the collision, with speeds
and in directions such that the total kinetic energy and vector-momentum
of both of them are equal to the total kinetic energy and vector-momentum
that Object-A had before the collision.
and in directions such that the total kinetic energy and vector-momentum
of both of them are equal to the total kinetic energy and vector-momentum
that Object-A had before the collision.
Answer:
Both objects will move
Explanation:
The collision is elastic, which means that both the total momentum and the total kinetic energy will be conserved after the collision. Therefore, we will have:
[tex]m_A u_A = m_A v_A + m_B v_B\\\frac{1}{2}m_A u_A^2 = \frac{1}{2}m_A v_A^2 + \frac{1}{2}m_B v_B^2[/tex]
where the first equation represents the conservation of the total momentum, while the second equation represents the conservation of the kinetic energy, and
[tex]u_A[/tex] is the velocity of object A before the collision
[tex]v_A[/tex] is the velocity of object A after the collision
[tex]v_B[/tex] is the velocity of object B after the collision
[tex]m_A = 500 kg, m_B=920 kg[/tex] are the masses of the two objects.