Question

A rocket blasts off. In 10.0 seconds it is at 10,000 ft, traveling at 3600 mph. Assuming the direction is up, calculate the acceleration. (Hint: the rocket is not under constant acceleration). 5280 ft/s2 528 ft/s2 100 ft/s2 200. ft/s2

Answer 1

       Acceleration  =  (change in speed)  /  (time for the change)

Change in speed = (ending speed) - (beginning speed)

                            =     (3,600 mi/hr) - ( 0 )

                            =       3,600 mi/hr

                            =     same as  1 mile/second.

Acceleration  =  (1 mi/sec) / (10 sec)

                      =     0.1 mi/sec² .

But 1 mile = 5,280 ft,
so
                       0.1 mi/s²  =  528 ft/s²          

Answer 2

A rocket blasts off. In 10.0 seconds it is at 10,000 ft, traveling at 3600 mph. Assuming the direction is up,  the acceleration of the rocket is not under constant acceleration is 528 ft/s2.

What is acceleration?

The rate of change of the velocity with respect to time is known as the acceleration of the object. Generally, the unit of acceleration is considered as meter/seconds².

Newton's three equations of motion are only applicable for the constant acceleration, the slope of the velocity time graph represents the acceleration of any object.

As we know the rate of change of velocity is known as acceleration

acceleration =change in velocity/change in time

First covert speed from miles per hour to miles per second

1 mile per hour = 1/3600 miles per second

    3600 mph     = 3600/3600 miles per seconds

                          = 1 miles per second

                          =3600 mph / 10 sconds

acceleration = 1 miles per second  / 10 seconds

                     =0.1 miles/ second²

Now we have to convert miles into feets

1 mile = 5280 feets

0.1 mile =528 feets

The acceleration of the rocket comes out to be 528 ft /s²

Learn more about acceleration from here

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