Respuesta :
The negative root of x^2+x-9=0 is -1/2 - (√37) / 2 ≈ -3.541, so the answer is:
between (–4, 0) and (–3, 0).
If you don't want to calculate the roots, you can verify that the x-axis is crossed between x=-4 and x=-3 by observing the sign of f change.
f(-4) = 16-4-9 = 3
f(-3) = 9-3-9 = -3
The sign changed (f went from 3 to -3) so it must have crossed the x-axis.
between (–4, 0) and (–3, 0).
If you don't want to calculate the roots, you can verify that the x-axis is crossed between x=-4 and x=-3 by observing the sign of f change.
f(-4) = 16-4-9 = 3
f(-3) = 9-3-9 = -3
The sign changed (f went from 3 to -3) so it must have crossed the x-axis.