Respuesta :
2 resonance structure.
O=S⁺-O⁻ and O⁻-S⁺=O, angles between S and O are 120°, bond order is 1,5.
O=S⁺-O⁻ and O⁻-S⁺=O, angles between S and O are 120°, bond order is 1,5.
Answer:
Two equivalent resonance forms can be drawn
Explanation:
In Lewis structure, total valence electrons of constituting atoms are used to draw structure by obeying octet of all atoms and duet of hydrogen atoms.
Least electronegative atom (except hydrogen atom) are considered as central atom.
In [tex]SO_{2}[/tex], S is the least electronegative atom. Hence it is the central atom.
Number of valence electron of S is 6 and valence electron of O is 6.
So, total number of valence electrons in [tex]SO_{2}[/tex] is 18.
By using this 18 electrons and obeying octet for S and O, two equivalent resonance forms can be drawn.
Structure of resonance forms has been given below.
![Ver imagen OrethaWilkison](https://us-static.z-dn.net/files/d77/a457bba07f5ae75945b0b78540e54d7e.png)