We can consider each unique [tex]t^i[/tex] as the as the [tex]i[/tex]-th unit vector. So your set [tex]s[/tex] can be considered as the vectors
[tex] \langle 1, 0, 0 \rangle, \langle 0, 1, 1 \rangle,\langle 0, 3, 4 \rangle[/tex]
Then check for independence your favorite way. In this case, I'll see if the linear map A of the new basis vectors doesn't map to a subspace via the determinant not being zero:
[tex] det(A) = det \left ( \left [ \begin{array}{ccc} 1 & 0 & 0 \\ 0 & 1 & 3 \\ 0 & 1 & 4 \end{array}\right ] \right ) = 1(4-3) = 1[/tex]
So they are linear independent.