Hello! First insert 6 where the h is located. So we have an equation that looks like the following. [tex]6 = 2 - 18t + 16t^2[/tex]
Although you could leave the equation in its original form, I am going to switch it around.
[tex]6 = 2 - 18t + 16t^2[/tex]
[tex]16t^2 - 18t + 2 = 6[/tex]
Move the 6 to the other side and do the math
[tex]16t^2 - 18t + 2 - 6 = 6 - 6[/tex]
[tex]16t^2 - 18t -4 = 0[/tex]
Factor and after factoring your T will be as follows
t = [tex]\frac{9}{16} - \frac{\sqrt{145}}{16}[/tex] = -0.1900
t = [tex]\frac{9}{16} + \frac{\sqrt{145}}{16}[/tex] = 1.315
