Question

The price of an item was increased twice by the same percent. By what percent was the second increase if the item became 1.44 times more expensive?

Please help!!!!!!

Answer 1

First, let's write this as an equation.

$f(x)=$ price of an item

$p=$ percent increase

$f(x)=xp^2$

$1.44x=xp^2$

$1.44=p^2$

$\sqrt{ 1.44}= \sqrt{p^2$

$p=1.2$

$1.2=120$%

Answer: The second price was a $120$% of the first price which means that the second increase was 20% more than the first price.

Hope this helps!