Probability theory predicts that there is a 9% chance of a water polo team winning any particular match. If the water polo team playing two matches is simulated 10,000 times, in about how many of the simulations would you expect them to win exactly one match?
A. 819
B. 81
C. 1638
D. 8281

The result is B. 1638.
9% = 0.09 is the probability of winning. The probability of losing is 1-0.09 = 0.91. To calculate the probability of winning the first match and losing the second one and vice versa, we will use the multiplication rule:1. 0.09 × 0.91 = 0.08192. 0.91 × 0.09 = 0.0819

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Probability theory predicts that there is a 9% chance of a water polo team winning any particular match. If the water polo team playing two matches is simulated 10,000 times, in about how many of the simulations would you expect them to win exactly one match? A. 819 B. 81 C. 1638 D. 8281

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Probability theory predicts that there is a 9% chance of a water polo team winning any particular match. If the water polo team playing two matches is simulated 10,000 times, in about how many of the simulations would you expect them to win exactly one match?
A. 819
B. 81
C. 1638
D. 8281