Respuesta :

log x would be like the first graph but pass though the point (1,0)

lg ( x - 1) would pass through (2,0)

so its the first graph

Logarithmic expressions can be represented on graphs

The graph that represents [tex]\mathbf{f(x) = log_2x - 1}[/tex] is graph (a)

The function is given as:

[tex]\mathbf{f(x) = log_2x - 1}[/tex]

Start by testing the options.

On graph (a), we have the following points

(x,y) =  (4,1) and (2,0)

Substitute the values for in the function

[tex]\mathbf{f(4) = log_2(4) - 1}[/tex]

Evaluate log(4)

[tex]\mathbf{f(4) = 2 - 1}[/tex]

[tex]\mathbf{f(4) = 1}[/tex]

Also, we have:

[tex]\mathbf{f(4) = log_2(2) - 1}[/tex]

Evaluate log(2)

[tex]\mathbf{f(4) = 1 - 1}[/tex]

[tex]\mathbf{f(4) = 0}[/tex]

These two points are true for [tex]\mathbf{f(x) = log_2x - 1}[/tex]

Hence, the graph that represents [tex]\mathbf{f(x) = log_2x - 1}[/tex] is graph (a)

Read more about graphs and functions at:

https://brainly.com/question/18806107

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