The answer is "0.949".
A sample of 100 students is selected from a known population of 1000 students = 100/1000 x 1/100 = 0.001
95% confidence interval for the average sat score = 95/100 = 0.95
correction factor used = 0.95 - 0.001 = 0.949
Thus, the correction factor used is 0.949.
