(1,105),(3,315)
slope = (315 - 105) / (3 - 1) = 210/2 = 105
y = mx + b
slope(m) = 105
use either of ur points....(1,105)...x = 1 and y = 105
now we sub and find b, the y int
105 = 1(105) + b
105 = 105 + b
105 - 105 = b
0 = b
so ur equation is : y = 105x + 0 which can be written as y = 105x
now to find a point on the line, sub in any number for x and solve for y
y = 105x....subbing in 2 for x
y = 105(2)
y = 210....so another point on the line is (2,210).....thats just one point, u can find more if u want....just sub in any number for x and solve for y