Respuesta :
Answer:
because i am in special ed
Step-by-step explanation:
that means i know everthing beacuse im special
Answer:
Common fractions = [tex]\frac{1}{2} ,\frac{1}{3} ,\frac{1}{6}=1[/tex]
Denominator = 6
combination of fruits in basket having 30 fruits :
[tex]\frac{1}{2} *30=\text{15 apples}\\ \\\frac{1}{3} *30=\text{10 oranges}\\\\\frac{1}{6} *30=\text{5 bananas}\\[/tex]
Combination of fruits in basket having 18 fruits :
[tex]\frac{1}{2} *18=\text{9 apples}\\ \\\frac{1}{3} *18=\text{6 oranges}\\\\\frac{1}{6} *18=\text{3 bananas}\\[/tex]
Combination of fruits in basket having 24 fruits :
[tex]\frac{1}{2} *24=\text{12 apples}\\ \\\frac{1}{3} *24=\text{8 oranges}\\\\\frac{1}{6} *24=\text{4 bananas}\\[/tex]
Combination of fruits in basket having 12 fruits :
[tex]\frac{1}{2} *12=\text{6 apples}\\ \\\frac{1}{3} *12=\text{4 oranges}\\\\\frac{1}{6} *12=\text{2 bananas}\\[/tex]
Step-by-step explanation:
Let x be fruits in any basket
Since we are given that . In every basket, 1/2 of the pieces of fruit must be apples, 1/3 must be oranges, and 1/6 must be bananas.
Thus in basket having x fruits will have apples = [tex]\frac{1}{2} x[/tex]
And oranges = [tex]\frac{1}{3} x[/tex]
bananas = [tex]\frac{1}{6} x[/tex]
So, no matter how much fruits there in a basket the fraction of apples , oranges and bananas will remain same
So, Common fractions = [tex]\frac{1}{2} ,\frac{1}{3} ,\frac{1}{6}[/tex]
Denominator = 6
Now combination of fruits in basket having 30 fruits :
Since we are given that 1/2 of the pieces of fruit must be apples, 1/3 must be oranges, and 1/6 must be bananas.
[tex]\frac{1}{2} *30=\text{15 apples}\\ \\\frac{1}{3} *30=\text{10 oranges}\\\\\frac{1}{6} *30=\text{5 bananas}\\[/tex]
Now combination of fruits in basket having 18 fruits :
Since we are given that 1/2 of the pieces of fruit must be apples, 1/3 must be oranges, and 1/6 must be bananas.
[tex]\frac{1}{2} *18=\text{9 apples}\\ \\\frac{1}{3} *18=\text{6 oranges}\\\\\frac{1}{6} *18=\text{3 bananas}\\[/tex]
Now combination of fruits in basket having 24 fruits :
Since we are given that 1/2 of the pieces of fruit must be apples, 1/3 must be oranges, and 1/6 must be bananas.
[tex]\frac{1}{2} *24=\text{12 apples}\\ \\\frac{1}{3} *24=\text{8 oranges}\\\\\frac{1}{6} *24=\text{4 bananas}\\[/tex]
Now combination of fruits in basket having 12 fruits :
Since we are given that 1/2 of the pieces of fruit must be apples, 1/3 must be oranges, and 1/6 must be bananas.
[tex]\frac{1}{2} *12=\text{6 apples}\\ \\\frac{1}{3} *12=\text{4 oranges}\\\\\frac{1}{6} *12=\text{2 bananas}\\[/tex]