Question

An acute angle θ is in a right triangle with cos θ = 9/10 . What is the value of sec θ?

Answer 1

sec θ=1/cos θ
cos θ=9/10, so sec θ=10/9

Answer 2

Answer:

The value of sec θ is $\frac{10}{9}$

Step-by-step explanation:

Given,

$cos \theta = \frac{9}{10}$

Since,

$cos \theta = \frac{1}{sec \theta}$

$\implies \frac{1}{sec \theta}=\frac{9}{10}$

By cross multiplication,

$10=9 sec \theta$

$\implies sec \theta = \frac{10}{9}$