19-12-2017
Mathematics

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Find the zeros of the function y= (x-2)(x+1)(x+3)

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19-12-2017

[tex]\bf y=(x-2)(x+1)(x+3)\implies 0=(x-2)(x+1)(x+3) \\\\\\ \begin{cases} 0=x-2\implies &~~2=x\\ 0=x+1\implies &-1=x\\ 0=x+3\implies &-3=x \end{cases}[/tex]

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