Answer:
Option (a) is correct.
(4, -1) lies on the graph of the equation 4x+3y = 13.
Step-by-step explanation:
Given : Equation of line is 4x + 3y = 13
We have to find out of given options which ordered pair lies on the graph of the equation 4x+3y = 13.
Consider the given equation of line 4x + 3y = 13.
Since, the ordered pair that satisfies the given equation will lies on the graph of the equation 4x+3y = 13.
Consider
A) (4, -1)
Put x = 4 and y = -1 in LHS of equation 4x + 3y = 13
4 (4) +3(-1) = 16 - 3 = 13
LHS = RHS
Thus, (4, -1) lies on the graph of the equation 4x+3y = 13.
B) (1, 6)
Put x = 1 and y = 6 in LHS of equation 4x + 3y = 13
4 (1) +3(6) = 4 + 18 = 22
LHS ≠ RHS
Thus, (1,6) does not lies on the graph of the equation 4x+3y = 13.
C) (0, -3)
Put x = 0 and y = -3 in LHS of equation 4x + 3y = 13
4 (0) +3(-3) = -9
LHS ≠ RHS
Thus, (0,-3) does not lies on the graph of the equation 4x+3y = 13.
D) (1, -3)
Put x = 1 and y = -3 in LHS of equation 4x + 3y = 13
4 (1) +3(-3) = 4 - 9 = 5
LHS ≠ RHS
Thus, (1, -3) does not lies on the graph of the equation 4x+3y = 13.
Thus, (4, -1) lies on the graph of the equation 4x+3y = 13.
