Sodium and water react according to the following equation. If 31.5g of sodium are added to excess water, how many liters of hydrogen gas are formed at STP? Show all work for credit.
first step: calculate the number of moles of sodium reacted moles=mass/molar mass 31.5g/23g/mol =1.37moles from the reaction above the reacting ratio of Na to H2 is 2:1 therefore moles of H2 is 1.37/2=0.685 At STP 1 mole = 22.4L what about 0.685 moles 22.4 x0.685=15.344L
