Question

hat is the center and radius of the circle with equation (x − 5)2 + (y + 3)2 = 16?

Answer 1

$\bf \textit{equation of a circle}\\\\ (x-{{ h}})^2+(y-{{ k}})^2={{ r}}^2 \qquad center~~(\stackrel{}{{{ h}}},\stackrel{}{{{ k}}})\qquad \qquad radius=\stackrel{}{{{ r}}}\\\\ -------------------------------\\\\ (x-5)^2+(y+3)^2=16\implies [x-\stackrel{h}{5}]^2+[y-(\stackrel{k}{-3})]^2=\stackrel{r~~2}{4}$