Question

consider the following system of equations 2x+3y=45 x+y=10 what is the x value of the solution for this system

Answer 1

x + y = 10.....y = 10 - x....so we sub in 10 - x for y in the other equation

2x + 3y = 45
2x + 3(10 - x) = 45
2x + 30 - 3x = 45
2x - 3x = 45 - 30
-x = 15
x = -15 <===

Answer 2

Answer:

value of x = -15

Step-by-step explanation:

Given the system of equation:

$2x+3y = 45$              .....[1]

$x+y = 10$                  ......[2]

Multiply equation [2] with 3 we have;

$3x+3y =30$          ......[3]

Subtract equation [3] from [1] to eliminate y and solve for x;

$2x+3y-3x-3y = 45-30$

Combine like terms;

$-x =15$

Divide both side by -1 we have;

x = -15

Therefore, the value of x of the solution for the given system is, -15