Question

The measure of ∠BCD is 120°. The measure of ∠ABC is 85°.



What is measure of ∠BAC?

Enter your answer in the box.

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A triangle A B C. Side A C is the base. A ray extends through vertex C and passes through a point labeled as D.

Answer 1

Answer: $\angle BAC=35^{\circ}$

Explanation:

Here, In $\triangle ABC$,  Side AC is the base. A ray extends through vertex C and passes through a point labeled as D.

And,  $\angle BCD=120^{\circ}$ and $\angle ABC=85^{\circ}$

Since, $\angle BCD$ is the exterior angle of the $\triangle ABC$

Therefore, by the property of exterior angle,

$\angle ABC+\angle BAC=120^{\circ}$

⇒$\angle BAC=120^{\circ}-85^{\circ}=35^{\circ}$

Answer 2

Answer:

35 degrees

Step-by-step explanation:

ABC is given 85*

BCD is given 120*

From BCD we can determine BCA which is 60*

85 plus 60= 145

180-145=35

BAC is 35*