algebra 2 unit 7 lesson 3
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The required equation of the circle with center (3, 5) and radius 8 is
(x - 3)² + (y - 5)² = 64. Option C is correct.
Given that,
A graph of the circle has shown, equation of the circle is to be determined.
The circle is the locus of a point whose distance from a fixed point is constant i.e center (h, k). The equation of the circle is given by
(x - h)² + (y - k)² = r²
where h, k is the coordinate of the center of the circle on the coordinate plane and r is the radius of the circle.
Here from the graph ceter of the circle is (3, 5) and radius of the circle is 8
So the equation of the circle is given as,
(x - h)² + (y - k)² = r²
(x - 3)² + (y - 5)² = 8²
(x - 3)² + (y - 5)² = 64
Thus, the required equation of the circle with center (3, 5) and radius 8 is
(x - 3)² + (y - 5)² = 64. Option C is correct.
Learn more about circle here:
brainly.com/question/11833983
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