Respuesta :
The sequence is geometric. The infinite series does converge.
Note how dividing any given term by the previous one leads to the same result
-8/12 = -2/3
(16/3) divided by -8 = -2/3
and so on...
So the common ratio is r = -2/3. This proves the sequence is geometric.
Since |r| < 1 is true, this means the infinite series converges to some fixed number.
Note how dividing any given term by the previous one leads to the same result
-8/12 = -2/3
(16/3) divided by -8 = -2/3
and so on...
So the common ratio is r = -2/3. This proves the sequence is geometric.
Since |r| < 1 is true, this means the infinite series converges to some fixed number.
We want to classify the given sequence, we will see that it is a geometric sequence.
So the given sequence is:
12, -8, 16/3, -32/9, 64/27
Because of the sign change, we can conclude that it is not an arithmetic sequence, then we can try to check if it is a geometric sequence.
It will be a geometric sequence if the ratio between two consecutive terms is always the same for any two consecutive terms we take.
Then let's see that:
[tex]\frac{-8}{12} = -0.666...[/tex]
[tex]\frac{16/3}{-8} = -0.666...[/tex]
[tex]\frac{-32/9}{16/3} = 0.666...[/tex]
And so on, so we can see that the ratio is always the same, meaning that this is a geometric sequence.
If you want to learn more, you can read:
https://brainly.com/question/13008517