Question

g(x) = x3 + 6x2 + 12x + 8Determine the function’s value when x = −1.


g(−1) = −3

g(−1) = 0

g(−1) = 1

g(−1) = 27

Answer 1

Plug in  -1 for x and  work it ou'

g(-1) = (-1)^3 + 6(-1)^2 + 12(-1) + 8

= -1 + 6 - 12 + 8

=  1

Answer 2

Answer:

The Answer is C. 1.

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