4[tex] \frac{1}{2} [/tex] + 6[tex] \frac{2}{3} [/tex] + 9[tex] \frac{1}{4} [/tex] = ?
Let's turn all these fractions to improper fractions to make it easier for us. 4[tex] \frac{1}{2} [/tex] would turn into [tex] \frac{9}{2} [/tex], 6[tex] \frac{2}{3} [/tex] would turn into [tex] \frac{20}{3} [/tex], and 9[tex] \frac{1}{4} [/tex] would turn into [tex] \frac{37}{4} [/tex].
So : [tex] \frac{9}{2} [/tex] + [tex] \frac{20}{3} [/tex] + [tex] \frac{37}{4} [/tex]
We would have to align the denominators to add them all together, and in aligning the denominators, we would have to change the numerators too. But to align the denominators, we would have to find the lowest common multiple between them all. The LCM is 12. Let's convert the denominators to 12. We would multiply the 2 with 6, the 3 with 4, and the 4 with 3. And what we do with the denominators, we do to numerators.
[tex] \frac{9}{2} [/tex] × [tex] \frac{6}{6} [/tex] = [tex] \frac{54}{12} [/tex]
[tex] \frac{20}{3} [/tex] × [tex] \frac{4}{4} [/tex] = [tex] \frac{80}{12} [/tex]
[tex] \frac{37}{4} [/tex] × [tex] \frac{3}{3} [/tex] = [tex] \frac{111}{12} [/tex]
Let's add all the numerators up. 54 + 80 + 111 = 245.
[tex] \frac{245}{12} [/tex]
That final answer can't be simplified, because I don't think they have any common factors.
