Answer:
Quotient = 2x³ -8x² + 5x - 7 and remainder = 8
Step-by-step explanation:
Given expression,
[tex]\frac{2x^4-4x^3-11x^2+3x-6}{x+2}[/tex]
By the long division method ( Shown below )
We get,
[tex]\frac{2x^4-4x^3-11x^2+3x-6}{x+2}=2x^3-8x^2+5x-7+\frac{8}{x+2}[/tex]
Hence, Quotient = 2x³ -8x² + 5x - 7,
Remainder = 8