Answer:
b. AB and XY, AC and XZ, BC and YZ.
Step-by-step explanation:
Given
two triangles ABC and XYZ
Corresponding side of AB is XY.
Corresponding side of BC is YZ.
Corresponding side of AC is XZ.
Desargues theorem: If two triangles ABC and A'B'C' in a plane .
The line AA', BB' and CC' intersect at a single point if and only if the intersection of corresponding sides (AB.A'B') ,(BC,B'C') and ( AC, A'C') lie on a single line.
Therefore, in given triangles ABC and XYZ the line AX, BY, CZ intersect at a single point .
Then the intersection of corresponding sides (AB,XY), (BC,YZ) and ( AC, XZ) lie on a single line.
By Desargues theorem w
we can say Side AB and XY, AC and XZ, BC and YZ are collinear.
Hence, option b is correct.