Respuesta :
heat of vaporization of water will be required as water is already at it's boiling point thus heat required will be 540*10=5400 cal
The heat required to convert the 10 g of water at 100 °C to steam at 100 °C is 5400 cal
Data obtained from the question
- Mass of water (M) = 10 g
- Temperature (T) = 100 °C
- Specific heat capacity (C) = 1 cal/gºC
- Heat of fusion (ΔHf) = 80 cal/g
- Heat of Vaporisation (ΔHv) = 540 cal/g
- Heat (Q) =?
Considering the question given above, the water is already at its boiling point (i.e 100 °C)
Thus, the heat needed to convert the water to steam can be obtained as follow:
How to determine the heat required
- Mass of water (M) = 10 g
- Heat of Vaporisation (ΔHv) = 540 cal/g
- Heat (Q) =?
Q = m × ΔHv
Q = 10 × 540
Q = 5400 cal
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