If a gas in a closed container is pressurized from 15.2 atmospheres to 19.2 atmospheres and its original temperature was 25.0oC, what would the final temperature of the gas be?
From the gay lussac law which the pressure of a given amount of a gas held at constant volume is directly proportional to temperature in kelvin. that is p1/T1=P2/T2 p1=15.2 atm P2=19.2 atm T1=25+273=298k T2=? 15.2/298=19.2/T2 5721.6=15.2 T2 divide both sides by 15.2 therefore T2=376.4k or 103.4 degrees celsius
