Question

Given that loga11 = 2.398, and loga5 = 1.609, find loga. 11/5

Answer 1

$\bf \textit{Logarithm of rationals}\\\\ log_{{ a}}\left( \frac{x}{y}\right)\implies log_{{ a}}(x)-log_{{ a}}(y)\\\\ -------------------------------\\\\ log_a\left( \frac{11}{5} \right)\implies log_a(11)-log_a(5)\implies 2.398~-~1.609\implies 0.789$