Question

If you have rectangular box with length = 40 cm, width = 30 cm, and height = 70 cm; what is the largest length stick that could fit inside the box (rounded to the nearest cm)

A) 80 cm
B) 86 cm
C) 90 cm
D) 96 cm

Answer 1

Call the box A'B'C'D'.ABCD
We have AC' as the longest possible length of the stick.
AC'^2 = A'C'^2 + C'C^2 = (40^2 + 30^2) + 70^2 = 7400
=> B as 86 x 86 = 7368

Answer 2

Answer:

86 cm

Step-by-step explanation:

We are given that

Length of rectangular box=40 cm

Width of rectangular  of x=30 cm

Height of rectangular box=70 cm

We have to find the largest length of stick that could fit inside the box.

Diagonal=$\sqrt{(40)^2+(30)^2}=\sqrt{1600+900}=\sqrt{2500}=50cm$ By using pythagorous theorem

Vertical diagonal across the box=$\sqrt{(70)^2+(50)^2}=\sqrt{4900+2500}=86$

Hence, the largest  length stick that could fit inside the box=86 cm