we know that
The volume of a cone is equal to
[tex]V=\frac{1}{3} \pi r^{2} h[/tex]
where
r is the radius of the base of the cone
h is the height of the cone
In this problem we have
[tex]r=2.5\ in\\h=1.6\ in[/tex]
substitute the values
[tex]V=\frac{1}{3}(3.14)(2.5^{2})(1.6)[/tex]
[tex]V=10.5\ in^{3}[/tex]
therefore
the answer is
[tex]10.5\ in^{3}[/tex]