Answer:
The maximum height of the particle is 100 ft
A is correct
Step-by-step explanation:
A particle is moving along a projectile path where the initial height is 96 feet with an initial speed of 16 feet per second.
The standard equation of parabolic projectile.
[tex]h(t)=-16t^2+v_0t+h_0[/tex]
where,
[tex]v_0=16\ ft/s[/tex]
[tex]h_0=96\ ft[/tex]
[tex]h(t)=-16t^2+16t+96[/tex]
So, we get the parabolic equation of path.
The maximum value at vertex.
[tex]t=-\dfrac{b}{2a}[/tex]
[tex]t=-\dfrac{16}{-32}=\dfrac{1}{2}[/tex]
Maximum at t=0.5
[tex]h(0.5)=-16(0.5)^2+16(0.5)+96[/tex]
[tex]h(0.5)=100[/tex]
Hence, The maximum height of the particle is 100 ft
Answer: 100 feet. A
Step-by-step explanation:
I took the test. Got it right
