Respuesta :

Recall that r^2 = x^2 + y^2, so that r = sqrt(x^2+y^2).

                                                                        y
r = 3 sin g becomes    sqrt(x^2+y^2) = 3*-----------------------
                                                                  sqrt(x^2+y^2)

Squaring both sides,

                    9y^2
x^2+y^2 = -----------------
                  x^2 + y^2

If this is correct (and I'm not convinced that it is), then (x^2+y^2)^2 = 9y^2
shows the relationship between x and y.  Can anyone improve on this result?

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