Answer:
CH4
Ar
Cl2
CH3COOH
Explanation:
Hello,
At first, methane is a compound that just has London dispersion forces which pretty much weak.
Next, argon has Van Der Waals, induced dipole, London dispersion and temporary dipole intermolecular forces which weak too but stronger than methane's.
After that, chlorine just have London dispersion forces, nevertheless they are stronger due to the chlorine's tendency to lose electrons and its high reactivity.
Finally, acetic acid has hydrogen bond, dipole-dipole and London acting intermolecular forces, that are by far stronger than the other substance's intermolecular forces.
Best regards.
