Question

What is the product? 4n/4n-4*n-1/n+1
A.)4n/n+1
B.)n/n+1
C.)1/n+1
D.)4/n+1

Answer 1

Answer:

B.) n/(n+1)

Step-by-step explanation:

$\dfrac{4n}{4n-4}\cdot\dfrac{n-1}{n+1}=\dfrac{4n(n-1)}{4(n-1)(n+1)}\\\\=\dfrac{n}{n+1}\qquad\text{factors of 4 and n-1 cancel}$

Answer 2

Answer:

option (b) is correct.

The product of $\frac{4n}{4n-4}$ and $\frac{n-1}{n+1}$ is $\frac{n}{n+1}$

Step-by-step explanation:

Given $\frac{4n}{4n-4}$ and $\frac{n-1}{n+1}$

We have to find the product of given two terms that is

$\frac{4n}{4n-4} \times \frac{n-1}{n+1}$

Consider the product written as ,

$\frac{4n}{4n-4} \times \frac{n-1}{n+1}$

Taking 4 common from the denominator of first term and simplify the first expression , we have,

$\frac{4n}{4(n-1)} \times \frac{n-1}{n+1}$

$\Rightarrow \frac{n}{(n-1)} \times \frac{n-1}{n+1}$

(n-1 ) in numerator get canceled by (n-1 ) in denominator, we have,

$\Rightarrow \frac{n}{n+1}$

Thus, option (b) is correct.

The product of $\frac{4n}{4n-4}$ and $\frac{n-1}{n+1}$ is $\frac{n}{n+1}$