Question

Troye has a number cube with the numbers 1 through 6 on it. Assuming each side is equally likely to appear when he rolls the cube, find the following probabilities. Note: when two or more numbers are multiplied, each of the numbers is a factor of the product.

a. P (rolls a 2)
b. P (rolls an odd number)
c. P (rolls a factor of 6)

Answer 1

Hey there, AdrienVallentino2047!

For letter a
Since there are six sides and only one of them contains the number 2 that means $\frac{1}{6}$ is the probability of getting the number 2, or 16.66%

For letter b
There are only three sides containing odd numbers: 1, 3 and 5
So, 3 out of the 6 sides contain an odd number
It would be $\frac{1}{2}$ in decimal or 50%

For letter c
Factor of six are two numbers that when you multiply them are equal to 6
We have
1 * 6 = 6 One number is 1
2 * 3 = 6 Another number is 2
3 * 2 = 6 Next number is 3
6 * 1 = 6 Last number is 6
So, we have four numbers in total that when you multiply them are equal to 6
Four sides out of the six are factors or 6
In fraction $\frac{4}{6}$
In percentage, 66.66%

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