Answer: SP=5 cm
Step-by-step explanation:
Since, Here PQRS is a kite where PR and SQ are the diagonals of the kite.
Let, PR is the major diagonal of the kite PQRS.
And let T is the intersection point of the diagonals.
Thus by the property of the kite diagonal PR bisect SQ with right angle.
⇒ [tex]\angle QTP=90^{\circ}[/tex]
Therefore, [tex]PQ=\sqrt{TP^2+TQ^2}[/tex]
⇒[tex]PQ=\sqrt{4^2+3^2}[/tex]=[tex]\sqrt{25} =5[/tex] ( we can not take the negative value of root)
But, PQ=SP
Therefore, SP= 5 cm
Note: If we take SQ as the major diagonal then we also get the same result.
