Question

Four identical 2500 kg objects are at the corners of a square with 12 m sides what is the distance between A and D

Answer 1

Please see attached diagram

We have square ABCD

Since ABCD is a square, all lines are of equal length

Therefore, lines AB, BC, CD and AD are 12m in length

If we draw a line from A to D, ACD forms a right angled triangle

The line AD is the hypotenuse of the right angled triangle ACD

Therefore, AC^2 + CD^2 = AD^2 (Pythagoras theorem)

AD^2 = 12^2 + 12^2

AD^2 = 144 + 144

AD^2 = 288

AD = 16.97

Therefore, the distance between A and D is 16.97m

Answer 2

Answer:

The distance between A and D will be 16.97m.

Explanation:

The identical objects are placed on the corners of the squre.

The corners can be designated as A, B, C and D.

The distance between A to B and B to D and C to D is equal and is 12m.

But the distance between A to D and C and B will be equal and different from 12m.

For measuring that distance, sketch a line between A and D.

The squre will be divided into two right angled triangle.

According to the Pythagoras theorem:

AD2 = AC2 + CD2

√AD2 = √(AC2 + CD2)

AD = √{(12)2 + (12)2)

AD = √144 +144

AD = √288

AD =  16.97m.

Hence the distance between A and D will be 16.97m.