Question

Factor the expression. 120k3 – 80k2 + 144k – 96

A (40k2 – 6)(24k + 2)
B 8(5k2 + 6)(3k – 2)
C (5k2 + 48)(3k – 16)
D 8(5k2 – 6)(3k + 2)

Answer 1

First...
$\mathrm{Rewrite\:as} \ \textgreater \ 8\cdot \:45k-8\cdot \:20k+8\cdot \:18k-8\cdot \:12$

$Then\; \mathrm{factor\:out\:the\;common\:term\:}8$
$8\left(45k+18k-20k-12\right)$

$Now\;refine\;8\left(43k-12\right)$

Hope this helps!

Answer 2

The answer to this question is:

B. 8(5k2 + 6)(3k – 2)