Respuesta :

[(1/3)^-2]/5*1=[(1/(1/3)^2)]/5=9/5



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[tex]\bf \left.\qquad \qquad \right.\textit{negative exponents}\\\\ a^{-{ n}} \implies \cfrac{1}{a^{ n}} \qquad \qquad \cfrac{1}{a^{ n}}\implies a^{-{ n}} \qquad \qquad a^{{{ n}}}\implies \cfrac{1}{a^{-{{ n}}}}\\\\ -------------------------------\\\\ \cfrac{f^{-2}}{5a}\quad \begin{cases} a=1\\ f=\frac{1}{3} \end{cases}\implies \cfrac{\left( \frac{1}{3} \right)^{-2}}{5(1)}\implies \cfrac{\left( \frac{3}{1} \right)^{2}}{5(1)}\implies \cfrac{\frac{3^2}{1^2}}{5}\implies \cfrac{9}{5}[/tex]
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