Given that point (-5, -6) is a point on the terminal side of θ. Since both the x coordinate and the y-coordinate are negative, θ is in the third quadrant.
The side opposite θ is -6 and the side adjacent θ is -5.
The hypothenus is given by [tex]\sqrt{(-6)^+(-5)^2}=\sqrt{36+25}=\sqrt{61}[/tex]
The exact value of cosθ is given by:
[tex]\cos\theta= \frac{adjacent}{hypothenuse} = \frac{-5}{\sqrt{61}} [/tex]
The exact value of cscθ is given by:
[tex]\csc\theta= \frac{hypothenuse}{opposite} = \frac{\sqrt{61}}{-6} [/tex]
The exact value of tanθ is given by:
[tex]\tan\theta= \frac{opposite}{adjacent} = \frac{-6}{-5} =1.2[/tex]
