Respuesta :

For this problem, we have to use the Planck's equation.

E = hv
where
E is the energy
h is Planck's constant equal to 6.626×10⁻³⁴ J·s
v is the frequency in Hz or s
⁻¹

Applying the equation, the answer would be:

E = (
6.626×10⁻³⁴ J·s)(5.49×10¹⁴ s⁻¹)
E = 3.64×10⁻¹⁹ J

The energy of the green light emitted, per photon, by a mercury lamp with a frequency of 5.49×10¹⁴ s⁻¹ is 3.64×10⁻¹⁹ J.

How do we calculate energy of photon?

Energy of photon of the green emitted light can be calculated as:

E = hυ, where

h = Planck's constant = 6.626×10⁻³⁴ J·s

υ = frequency in Hz or s⁻¹ = 5.49×10¹⁴ s⁻¹

On putting values, we get the equation

E = (6.626×10⁻³⁴ J·s)(5.49×10¹⁴ s⁻¹)

E = 3.64×10⁻¹⁹ J

Hence the required energy is 3.64×10⁻¹⁹ J.

To know more about photon energy, visit the below link:

https://brainly.com/question/25746629

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