Respuesta :
For this problem, we have to use the Planck's equation.
E = hv
where
E is the energy
h is Planck's constant equal to 6.626×10⁻³⁴ J·s
v is the frequency in Hz or s⁻¹
Applying the equation, the answer would be:
E = (6.626×10⁻³⁴ J·s)(5.49×10¹⁴ s⁻¹)
E = 3.64×10⁻¹⁹ J
E = hv
where
E is the energy
h is Planck's constant equal to 6.626×10⁻³⁴ J·s
v is the frequency in Hz or s⁻¹
Applying the equation, the answer would be:
E = (6.626×10⁻³⁴ J·s)(5.49×10¹⁴ s⁻¹)
E = 3.64×10⁻¹⁹ J
The energy of the green light emitted, per photon, by a mercury lamp with a frequency of 5.49×10¹⁴ s⁻¹ is 3.64×10⁻¹⁹ J.
How do we calculate energy of photon?
Energy of photon of the green emitted light can be calculated as:
E = hυ, where
h = Planck's constant = 6.626×10⁻³⁴ J·s
υ = frequency in Hz or s⁻¹ = 5.49×10¹⁴ s⁻¹
On putting values, we get the equation
E = (6.626×10⁻³⁴ J·s)(5.49×10¹⁴ s⁻¹)
E = 3.64×10⁻¹⁹ J
Hence the required energy is 3.64×10⁻¹⁹ J.
To know more about photon energy, visit the below link:
https://brainly.com/question/25746629
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