Respuesta :

1)
(x+3)(x+5)=
x*x+x*5+3*x+3*5=
x^2+5x+3x+15=
x^2+8x+15
2)
(x+3)(x-5)=
x*x+x*(-5)+3*x+3*(-5)=
x^2-5x+3x-15=
x^2-2x-15
3)
(x-3)(x-5)=
x*x+x*(-5)+(-3)*x+(-3)*(-5)=
x^2-5x-3x+15=
x^2-8x+15
4)
(2x+4)(x-7)=
(2x)*x+(2x)*(-7)+4*x+4*(-7)=
2x^2-14x+4x-28=
2x^2-10x-28
#1.

[tex](x+3)(x+5)[/tex]
[tex]x^2+5x+3x+15[/tex]
[tex]x^2+8x+15 [/tex]

#2.

[tex](x+3)(x-5)[/tex]
[tex]x^2-5x+3x-15[/tex]
[tex]x^2-2x-15[/tex]

#3.

[tex](x-3)(x-5)[/tex]
[tex]x^2-5x-3x+15[/tex]
[tex]x^2-8x+15[/tex]

#4.

[tex](2x+4)(x-7)[/tex]
[tex]2x^2-14x+4x-28[/tex]
[tex]2x^2-10x-28[/tex]


Hope I've Helped!
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