Respuesta :
The figure needed to answer the question is attached.
You can split the pentagon in two figures: a) a rectangle with side lentghs equal to 14 inches and 8 inches, and b) a right isosceles triangle with base 10 inches and height 10 inches.
a) area of the rectangle: base * height = 14in * 8 in = 112 in^2
b) area of the triangle: (1/2) base * height = (1/2) 10 in * 10 in = 50 in^2
Area of the pentagon = 112 in^2 + 50 in^2 = 162 in^2
Area of 4 pentagons = 4 * 162 in^2 = 648 in^2.
Answer: option C. 648 in^2
You can split the pentagon in two figures: a) a rectangle with side lentghs equal to 14 inches and 8 inches, and b) a right isosceles triangle with base 10 inches and height 10 inches.
a) area of the rectangle: base * height = 14in * 8 in = 112 in^2
b) area of the triangle: (1/2) base * height = (1/2) 10 in * 10 in = 50 in^2
Area of the pentagon = 112 in^2 + 50 in^2 = 162 in^2
Area of 4 pentagons = 4 * 162 in^2 = 648 in^2.
Answer: option C. 648 in^2
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Answer:
Option C id the correct answer.
Step-by-step explanation:
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